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The Invoke( ) method defined by Parallel lets you execute one or more methods by simply specifying them as arguments If possible, it scales to utilize the available processors Its simplest version is defined like this: public static void Invoke(params Action[ ] actions) The methods to be executed must be compatible with the Action delegate that was described earlier Recall that Action is declared like this: public delegate void Action( ) Therefore, each method passed to Invoke( ) must have no parameters and must return void Because actions is a params parameter, you can specify a variable-length argument list of methods to execute You can also use an array of Action, but often the argument list is easier Invoke( ) will initiate execution of all of the methods that it is passed It will then wait until all of the methods have finished Thus, there is no need (nor ability) to call Wait( ), for example Invoke( ) handles all the details Although there is no guarantee that the methods will execute in parallel, this is the expectation if the system supports more than one processor Also, the order of execution, including which method starts or finishes first, cannot be specified, and may not be the same as the order as the argument list The following program demonstrates Invoke( ) It runs two methods, called MyMeth( ) and MyMeth2( ), via a call to Invoke( ) Notice the simplicity of the process

x=1/2

// Use ParallelInvoke() to execute methods concurrently using System; using SystemThreading; using SystemThreadingTasks; class DemoParallel { // A method to be run as a task static void MyMeth() { ConsoleWriteLine("MyMeth starting"); for(int count = 0; count < 5; count++) { ThreadSleep(500); ConsoleWriteLine("In MyMeth, count is " + count ); } ConsoleWriteLine("MyMeth terminating"); } // A method to be run as a task static void MyMeth2() { ConsoleWriteLine("MyMeth2 starting"); for(int count = 0; count < 5; count++) { ThreadSleep(500); ConsoleWriteLine("In MyMeth2, count is " + count ); }

Adhering to the principle of parallel construction, it would be better to write:

24:

M u l t i t h r e a d i n g , P a r t Tw o : E x p l o r i n g t h e Ta s k P a r a l l e l L i b r a r y a n d P L I N Q

Define the function Tan x to be the restriction of tan x to the interval ( /2, /2) Observe that the tangent function is undefined at the endpoints of this interval Since d 2 Tan x = sec x dx we see that Tan x is increasing, hence it is one-to-one (Figure 619) Also Tan takes arbitrarily large positive values when x is near to, but less than, /2 And Tan takes negative values that are arbitrarily large in absolute value when x is near to, but greater than, /2 Therefore, Tan takes all real values Since Tan : 1 ( /2, /2) ( , ) is one-to-one and onto, the inverse function Tan : ( , ) ( /2, /2) exists The graph of this inverse function is shown in Figure 620 It is obtained by the usual procedure of reflecting in the line y = x

ConsoleWriteLine("MyMeth2 terminating"); } static void Main() { ConsoleWriteLine("Main thread starting"); // Run two named methods ParallelInvoke(MyMeth, MyMeth2); ConsoleWriteLine("Main thread ending"); }

The output is shown here:

Main thread starting MyMeth starting MyMeth2 starting In MyMeth, count is 0 In MyMeth2, count is 0 In MyMeth, count is 1 In MyMeth2, count is 1 In MyMeth, count is 2 In MyMeth2, count is 2 In MyMeth, count is 3 In MyMeth2, count is 3 In MyMeth, count is 4 MyMeth terminating In MyMeth2, count is 4 MyMeth2 terminating Main thread ending

There is something very important to notice in this example: Main( ) suspends until Invoke( ) returns Therefore, even though MyMeth( ) and MyMeth2( ) are executing concurrently, Main( ) is not If you want the calling thread to continue execution, you can t use Invoke( ) as shown here Although the previous example used named methods, this is not required when calling Invoke( ) Here is the same program reworked to use lambda expressions as arguments to Invoke( ):

Tan 1 1, Tan 1 1/ 3, Tan 1 ( 3)