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One is negative, the other positive It makes good business sense to write with a positive, not a negative, focus For instance:

tskWait(); tsk2Wait();

x=1/3

TaskWaitAll(tsk, tsk2);

The program will work the same, but the logic is cleaner and more compact When waiting for multiple tasks, you need to be careful about deadlocks If two tasks are waiting on each other, then a call to WaitAll( ) will never return Of course, deadlock conditions are errors that you must avoid Therefore, if a call to WaitAll( ) does not return, consider the possibility that two or more of the tasks could be deadlocking (A call to Wait( ) that doesn t return could also be the result of deadlock) Sometimes you will want to wait until any one of a group of tasks completes To do this, use the WaitAny( ) method Here is its simplest form: public static int WaitAny(params Task[ ] tasks) The tasks that you want to wait for are passed via tasks The tasks can be passed either as an array of Task objects or separately as a list of Task arguments It returns the index of the task that completes first Various exceptions are possible You can try WaitAny( ) in the previous program by substituting this call:

TaskWaitAny(tsk, tsk2);

Now, as soon as one task finishes, Main( ) resumes and the program ends In addition to the forms of Wait( ), WaitAll( ), and WaitAny( ) shown here, there are versions that let you specify a timeout period or watch for a cancellation token (Task cancellation is described later in this chapter)

We have d Sin 1 x dx d Sin 1 ( x 2 + x) dx d Sin 1 ( 1/x) dx 1 1 x2 1 1 ( x2 1 1 ( 1/x) 2 + x) 2

Calling Dispose( )

The Task class implements the IDisposable interface, which specifies the Dispose( ) method It has this form: public void Dispose( ) As implemented by Task, Dispose( ) releases the resources used by the Task In general, the resources associated with a Task are automatically released when the Task is subjected to

Part II:

While you want to make your points clearly and honestly, you want to maintain as positive a tone as you can

2, 15 65 1 6

garbage collection (or when the program terminates) However, to release those resources before then, call Dispose( ) This is especially important in a program in which large numbers of tasks are created and then abandoned It is important to understand that Dispose( ) can be called on a task only after it has completed Thus, you will need to use some mechanism, such as Wait( ), to determine that a task has completed before calling Dispose( ) This is why it was necessary to describe the Wait( ) method prior to discussing Dispose( ) It you do try to call Dispose( ) on a still active task, an InvalidOperationException will be generated Because all of the examples in this chapter create few tasks, are quite short, and end immediately, calls to Dispose( ) are of essentially no benefit (This is why it was not necessary to call Dispose( ) in the preceding programs; they all end as soon as the tasks end, thus resulting in the disposal of the tasks) However, so as to demonstrate its use and to avoid confusion in this regard, all subsequent examples will call Dispose( ) explicitly when working directly with Task instances However, don t be surprised if you see example code from other sources that do not Again, if a program will be ending as soon as a task ends, then there is essentially no point is calling Dispose( ) aside from demonstrating its use