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There are various ways to create a new Task and start its execution We will begin by first creating a Task using a constructor and then starting it by calling the Start( ) method Task defines several constructors Here is the one we will be using: public Task(Action action) Here, action is the entry point of the code that represents the task Action is a delegate defined in System It has several forms Here is the form we will use now: public delegate void Action( ) Thus, the entry point must be a method that takes no parameters and returns void (As you will see later, it is possible to specify an argument to Action)

cash ten years from now The endowment will be set up today with $5,000 principal and locked in at a fixed interest rate What interest rate (compounded continuously) is needed to guarantee the desired payoff

24:

E-mails Given that E-mails are usually shorter than other forms of communication, they usually feature only one category of content Longer E-mails, however, can be divided into content categories Julie Ann explained that as a purchasing agent for an industrial belting company, she communicates with vendors via E-mail all the time What I ve found most effective is listing my questions and asking that they respond to them one by one In other words, I set the categories for their responses

M u l t i t h r e a d i n g , P a r t Tw o : E x p l o r i n g t h e Ta s k P a r a l l e l L i b r a r y a n d P L I N Q

Once a task has been created, you can start it by calling Start( ) One version is shown here: public void Start( ) After a call to Start( ), the task scheduler schedules it for execution The following program puts the preceding discussion into action It creates a separate task based on the MyTask( ) method After Main( ) starts, the task is created and then started Both MyTask( ) and Main( ) execute concurrently

Figure 614 shows the graphs of each of the six trigonometric functions Notice that each graph has the property that some horizontal line intersects the graph at least twice Therefore none of these functions is invertible Another way of seeing this point is that each of the trigonometric functions is 2 -periodic (that is, the function repeats itself every 2 units: f (x + 2 ) = f (x)), hence each of these functions is not one-to-one If we want to discuss inverses for the trigonometric functions, then we must restrict their domains (this concept was introduced in Subsection 185) In this

// Create and run a task using System; using SystemThreading; using SystemThreadingTasks; class DemoTask { // A method to be run as a task static void MyTask() { ConsoleWriteLine("MyTask() starting"); for(int count = 0; count < 10; count++) { ThreadSleep(500); ConsoleWriteLine("In MyTask(), count is " + count); } ConsoleWriteLine("MyTask terminating"); } static void Main() { ConsoleWriteLine("Main thread starting"); // Construct a task Task tsk = new Task(MyTask); // Run the task tskStart(); // Keep Main() alive until MyTask() finishes for(int i = 0; i < 60; i++) { ConsoleWrite(""); ThreadSleep(100); } ConsoleWriteLine("Main thread ending"); } }

The output is shown here (The precise output that you see may differ slightly based on task load, operating system, etc)

Part II:

section we learn the standard methods for performing this restriction operation with the trigonometric functions

In MyTask(), count is 0 In MyTask(), count is 1 In MyTask(), count is 2 In MyTask(), count is 3 In MyTask(), count is 4 In MyTask(), count is 5 In MyTask(), count is 6 In MyTask(), count is 7 In MyTask(), count is 8 In MyTask(), count is 9 MyTask terminating Main thread ending