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Description ANDs the bits of the invoking object with those specified by value and returns a BitArray that contains the result Returns the value of the bit at the index specified by index Performs a bitwise, logical NOT on the invoking collection and returns a BitArray that contains the result ORs the bits of the invoking object with those specified by value and returns a BitArray that contains the result Sets the bit at the index specified by index to value Sets all bits to value XORs the bits of the invoking object with those specified by value and returns a BitArray that contains the result

TABLE 25-9

The turnaround time from rst report to completed repair has taken, on average, 23 percent longer than it did last year

Part II:

[Notice that the quadratic polynomial in the denominator will factor precisely when the discriminant is 0, which is case IV from Subsection 721] Our goal is to write the fraction on the right-hand side of ( ) as a sum of simpler fractions With this thought in mind, we write A B 1 = + , ( x 1) ( x 2) x 1 x 2

To the properties specified by the interfaces that it implements, BitArray adds Length, which is shown here: public int Length { get; set; } Length sets or obtains the number of bits in the collection Thus, Length gives the same value as does the standard Count property, which is defined for all collections However, Count is read-only, but Length is not Thus, Length can be used to change the size of a BitArray If you shorten a BitArray, bits are truncated from the high-order end If you lengthen a BitArray, false bits are added to the high-order end BitArray defines the following indexer: public bool this[int index] { get; set; } You can use this indexer to get or set the value of an element Here is an example that demonstrates BitArray:

// Demonstrate BitArray using System; using SystemCollections; class BADemo { public static void ShowBits(string rem, BitArray bits) { ConsoleWriteLine(rem); for(int i=0; i < bitsCount; i++) ConsoleWrite("{0, -6} ", bits[i]); ConsoleWriteLine("\n"); } static void Main() { BitArray ba = new BitArray(8); byte[] b = { 67 }; BitArray ba2 = new BitArray(b); ShowBits("Original contents of ba:", ba); ba = baNot(); ShowBits("Contents of ba after Not:", ba); ShowBits("Contents of ba2:", ba2); BitArray ba3 = baXor(ba2); ShowBits("Result of ba XOR ba2:", ba3); } }

The output is shown here:

25:

where A and B are constants to be determined Let us put together the two fractions on the right by placing them over the common denominator ( x 1) ( x 2) Thus A B A( x 2) + B( x 1) 1 = + = ( x 1) ( x 2) x 1 x 2 ( x 1) ( x 2) The only way that the fraction on the far left can equal the fraction on the far right is if their numerators are equal This observation leads to the equation 1 = A( x 2) + B( x 1) or 0 = ( A + B) x + ( 2A B 1) Now this equation is to be identically true in x; in other words, it must hold for every value of x So the coefficients must be 0 At long last, then, we have a system of two equations in two unknowns: A+B =0

The NET Framework provides some specialized collections that are optimized to work on a specific type of data or in a specific way These non-generic collection classes are defined inside the SystemCollectionsSpecialized namespace They are synopsized in the following table: